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x^2+68x-72.25=0
a = 1; b = 68; c = -72.25;
Δ = b2-4ac
Δ = 682-4·1·(-72.25)
Δ = 4913
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4913}=\sqrt{289*17}=\sqrt{289}*\sqrt{17}=17\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-17\sqrt{17}}{2*1}=\frac{-68-17\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+17\sqrt{17}}{2*1}=\frac{-68+17\sqrt{17}}{2} $
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